y=1/2x^2+x+2

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Solution for y=1/2x^2+x+2 equation:


x in (-oo:+oo)

y = (1/2)*x^2+x+2 // - (1/2)*x^2+x+2

y-((1/2)*x^2)-x-2 = 0

(-1/2)*x^2-x+y-2 = 0

y-1/2*x^2-x-2 = 0

DELTA = (-1)^2-(-1/2*4*(y-2))

DELTA = 2*(y-2)+1

2*(y-2)+1 = 0

2*(y-2)+1 = 0

2*y-3 = 0

2*y-3 = 0

2*y-3 = 0 // + 3

2*y = 3 // : 2

y = 3/2

DELTA = 0 <=> t_1 = 3/2

x = 1/(-1/2*2) i y = 3/2

x = -1 i y = 3/2

( x = ((2*(y-2)+1)^(1/2)+1)/(-1/2*2) or x = (1-(2*(y-2)+1)^(1/2))/(-1/2*2) ) i y > 3/2

( x = -((2*(y-2)+1)^(1/2)+1) or x = (2*(y-2)+1)^(1/2)-1 ) i y > 3/2

y-(3/2) > 0

y-3/2 > 0

y-3/2 > 0 // + 3/2

y > 3/2

x in { -1, -((2*(y-2)+1)^(1/2)+1), (2*(y-2)+1)^(1/2)-1 }

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